van der Waals correction

A correction on top of the PBE functional has been proposed by Tkachenko and Scheffler [1]. While nearly all parameters are obtained from ab-initio calculations, the method requires nearly no additional computational cost and performs very well:

. PBE TPSS vdW-DF vdW-DF2 TS09
Mean deviation 115 154 76 48 15
RMS deviation 108 128 60 42 15

Error in energies compared to CCSD results of the S26 test set. All values in meV. GPAW calculations were done with h=0.18 and at least 4 A vacuum. The TS09 results are in good agreement to the results obtained with the FHI-aims code [2].

Calculating the S26 test set

As an example of the usage, here the S26 test set is calculated:

from __future__ import print_function
from ase import Atoms
from ase.parallel import paropen
from import data
from ase.calculators.vdwcorrection import vdWTkatchenko09prl
from gpaw import GPAW, FermiDirac
from gpaw.cluster import Cluster
from gpaw.analyse.hirshfeld import HirshfeldPartitioning
from gpaw.analyse.vdwradii import vdWradii
h = 0.18
box = 4.
xc = 'TS09'
f = paropen('energies_' + xc + '.dat', 'w')
print('# h=', h, file=f)
print('# box=', box, file=f)
print('# molecule E[1]  E[2]  E[1+2]  E[1]+E[2]-E[1+2]', file=f)
for molecule in data:
    print(molecule, end=' ', file=f)
    ss = Cluster(Atoms(data[molecule]['symbols'],
    # split the structures
    s1 = ss.find_connected(0)
    s2 = ss.find_connected(-1)
    assert(len(ss) == len(s1) + len(s2))
    if xc == 'TS09' or xc == 'TPSS' or xc == 'M06-L':
        c = GPAW(xc='PBE', h=h, nbands=-6, occupations=FermiDirac(width=0.1))
        c = GPAW(xc=xc, h=h, nbands=-6, occupations=FermiDirac(width=0.1))
    E = []
    for s in [s1, s2, ss]:
        s.minimal_box(box, h=h)
        if xc == 'TS09':
            cc = vdWTkatchenko09prl(HirshfeldPartitioning(c),
                                    vdWradii(s.get_chemical_symbols(), 'PBE'))
        if xc == 'TPSS' or xc == 'M06-L':
            ene = s.get_potential_energy()
            ene += c.get_xc_difference(xc)
    print(E[0], E[1], E[2], end=' ', file=f)
    print(E[0] + E[1] - E[2], file=f)
[1]Tkachenko and Scheffler Phys. Rev. Lett. 102 (2009) 073005
[2]Felix Hanke J. Comp. Chem. 32 (2011) 1424